Aplicamos a regra: $\frac{\frac{a}{b}}{c}$$=\frac{a}{bc}$, onde $a=taylor$, $b=\mathrm{sinh}\left(z\right)$, $c=z^4\left(1-z^2\right)$, $a/b/c=\frac{\frac{taylor}{\mathrm{sinh}\left(z\right)}}{z^4\left(1-z^2\right)}$ e $a/b=\frac{taylor}{\mathrm{sinh}\left(z\right)}$