Aprenda online a resolver problemas complete o quadrado passo a passo. 9t^2-6t+-2. Aplicamos a regra: ax^2+bx+c=a\left(x^2+\frac{b}{a}x+\frac{c}{a}\right), onde a=9, b=-6, c=-2 e x=t. Aplicamos a regra: a\left(x^2+b+c\right)=a\left(x^2+b+c+\left(\frac{coef\left(b\right)}{2}\right)^2-\left(\frac{coef\left(b\right)}{2}\right)^2\right), onde a=9, b=-\frac{2}{3}t, c=-\frac{2}{9} e x=t. Aplicamos a regra: a\left(x^2+b+c+f+g\right)=a\left(\left(x+\sqrt{f}sign\left(b\right)\right)^2+c+g\right), onde a=9, b=-\frac{2}{3}t, c=-\frac{2}{9}, x^2+b=t^2-\frac{2}{3}t-\frac{2}{9}+\frac{1}{9}-\frac{1}{9}, f=\frac{1}{9}, g=-\frac{1}{9}, x=t e x^2=t^2. Aplicamos a regra: \frac{a}{b}c=\frac{ca}{b}, onde a=1, b=3, c=-1, a/b=\frac{1}{3} e ca/b=- \frac{1}{3}.

9t^2-6t+-2