Aprenda online a resolver problemas complete o quadrado passo a passo. 4b^2-26b+169. Aplicamos a regra: ax^2+bx+c=a\left(x^2+\frac{b}{a}x+\frac{c}{a}\right), onde a=4, b=-26, c=169 e x=b. Aplicamos a regra: a\left(x^2+b+c\right)=a\left(x^2+b+c+\left(\frac{coef\left(b\right)}{2}\right)^2-\left(\frac{coef\left(b\right)}{2}\right)^2\right), onde a=4, b=-\frac{13}{2}b, c=\frac{169}{4} e x=b. Aplicamos a regra: a\left(x^2+b+c+f+g\right)=a\left(\left(x+\sqrt{f}sign\left(b\right)\right)^2+c+g\right), onde a=4, b=-\frac{13}{2}b, c=\frac{169}{4}, x^2+b=b^2-\frac{13}{2}b+\frac{169}{4}+\frac{169}{16}-\frac{169}{16}, f=\frac{169}{16}, g=-\frac{169}{16}, x=b e x^2=b^2. Aplicamos a regra: \frac{a}{b}c=\frac{ca}{b}, onde a=13, b=4, c=-1, a/b=\frac{13}{4} e ca/b=- \frac{13}{4}.

4b^2-26b+169