Exercício
$\int_1^3\left(\sqrt{1\:+\frac{1}{2\sqrt{x}}}\right)dx$
Solução explicada passo a passo
Resposta final para o problema
$\frac{1}{4}\sqrt{\left(2\sqrt{3}+\frac{1}{2}\right)^2-\frac{1}{4}}\cdot \left(2\sqrt{3}+\frac{1}{2}\right)+\frac{1}{16}\ln\left|4\sqrt{3}+1+2\sqrt{\left(2\sqrt{3}+\frac{1}{2}\right)^2-\frac{1}{4}}\right|-\frac{1}{8}\ln\left|4\sqrt{3}+1+2\sqrt{\left(2\sqrt{3}+\frac{1}{2}\right)^2-\frac{1}{4}}\right|-\left(\frac{1}{4}\sqrt{\left(2\sqrt{1}+\frac{1}{2}\right)^2-\frac{1}{4}}\cdot \left(2\sqrt{1}+\frac{1}{2}\right)+\frac{1}{16}\ln\left|4\sqrt{1}+1+2\sqrt{\left(2\sqrt{1}+\frac{1}{2}\right)^2-\frac{1}{4}}\right|-\frac{1}{8}\ln\left|4\sqrt{1}+1+2\sqrt{\left(2\sqrt{1}+\frac{1}{2}\right)^2-\frac{1}{4}}\right|\right)$