Exercício
$\int_0^2\sqrt{x^2+1\:x}dx$
Solução explicada passo a passo
Resposta final para o problema
$\frac{1}{2}\sqrt{\left(2+\frac{1}{2}\right)^2-\frac{1}{4}}\cdot \left(2+\frac{1}{2}\right)+\frac{1}{8}\ln\left|2\cdot 2+1+2\sqrt{\left(2+\frac{1}{2}\right)^2-\frac{1}{4}}\right|-\frac{1}{4}\ln\left|2\cdot 2+1+2\sqrt{\left(2+\frac{1}{2}\right)^2-\frac{1}{4}}\right|-\left(\frac{1}{2}\sqrt{\left(0+\frac{1}{2}\right)^2-\frac{1}{4}}\cdot \left(0+\frac{1}{2}\right)+\frac{1}{8}\ln\left|2\cdot 0+1+2\sqrt{\left(0+\frac{1}{2}\right)^2-\frac{1}{4}}\right|-\frac{1}{4}\ln\left|2\cdot 0+1+2\sqrt{\left(0+\frac{1}{2}\right)^2-\frac{1}{4}}\right|\right)$