Exercício
$\int_{\frac{\pi}{6}}^{\frac{\pi}{4}}\left(sen2x+cos2x\right)^2dx$
Solução explicada passo a passo
Resposta final para o problema
$-4\cdot \left(\frac{1}{16}+\frac{3}{4}\cdot \left(\frac{1}{2}\cdot \frac{\pi }{4}+\frac{1}{4}\right)+\frac{-\frac{1}{2}\cdot \cos\left(\frac{\pi }{6}\right)^{3}}{4}+\left(\frac{1}{2}\cdot \frac{\pi }{6}+\frac{1}{4}\cdot \frac{3^{0.5}}{2}\right)-\frac{3}{4}\right)+\frac{-4\cdot 3^{0.5}}{8}-\frac{\pi }{3}+\frac{5.1415927}{2}+\frac{1}{4}\cos\left(\frac{2\pi }{3}\right)+\frac{1}{4}-\frac{1}{2}\cdot \left(\frac{\pi }{6}+\frac{1}{4}\sin\left(\frac{2\pi }{3}\right)\right)+\frac{1}{2}\cdot \frac{\pi }{4}$