Exercício
$\frac{d}{dx}\left(ln\left(\frac{3-x}{3+x}\right)\right)$
Solução explicada passo a passo
Aprenda online a resolver problemas derivada da soma passo a passo. d/dx(ln((3-x)/(3+x))). Aplicamos a regra: \frac{d}{dx}\left(\ln\left(x\right)\right)=\frac{1}{x}\frac{d}{dx}\left(x\right). Aplicamos a regra: \frac{a}{\frac{b}{c}}=\frac{ac}{b}, onde a=1, b=3-x, c=3+x, a/b/c=\frac{1}{\frac{3-x}{3+x}} e b/c=\frac{3-x}{3+x}. Aplicamos a regra: \frac{d}{dx}\left(\frac{a}{b}\right)=\frac{\frac{d}{dx}\left(a\right)b-a\frac{d}{dx}\left(b\right)}{b^2}, onde a=3-x e b=3+x. Aplicamos a regra: \frac{a}{b}\frac{c}{f}=\frac{ac}{bf}, onde a=3+x, b=3-x, c=\frac{d}{dx}\left(3-x\right)\left(3+x\right)-\left(3-x\right)\frac{d}{dx}\left(3+x\right), a/b=\frac{3+x}{3-x}, f=\left(3+x\right)^2, c/f=\frac{\frac{d}{dx}\left(3-x\right)\left(3+x\right)-\left(3-x\right)\frac{d}{dx}\left(3+x\right)}{\left(3+x\right)^2} e a/bc/f=\frac{3+x}{3-x}\frac{\frac{d}{dx}\left(3-x\right)\left(3+x\right)-\left(3-x\right)\frac{d}{dx}\left(3+x\right)}{\left(3+x\right)^2}.
Resposta final para o problema
$\frac{-3-x-3+x}{9-x^2}$